mysql изберете низ с максимална стойност, по сгруппированным
SELECT t1.*
FROM employees t1
INNER JOIN (
SELECT id, max(salary) AS salary FROM employees GROUP BY id
) t2 ON t1.id = t2.id AND t1.salary = t2.salary;
SQL получава най-доброто за идентификатор
select name, max(value)
from out_pumptable
group by name
mysql, скупчени на максималната стойност
-- MySql: First result only returned, so Person with max age in each Group
select *
from (select * from mytable order by `Group`, age desc, Person) x
group by `Group`;